Calculation For Cable Size _verified_ ★

$$I_cable \ge I_load$$

Ensure cable withstands fault current without insulation damage. Adiabatic equation (IEC 60364-5-54): [ S = \frac\sqrtI_sc^2 \times tk ] calculation for cable size

You would select $2.5 , mm^2$ to be safe. $$I_cable \ge I_load$$ Ensure cable withstands fault current

$$A = \frac20.646.9 \approx 2.99 , mm^2$$ mm^2$$ (V_d \leq \textpermissible drop) (e.g.

(V_d \leq \textpermissible drop) (e.g., 3% of 400V = 12V). If drop exceeds limit, select next larger cable size and re-check.

Cable current-carrying capacity (ampacity) must be derated based on: